How do I figure out time and date at the same time?

Dear all,
I've got some problems with date and time (very silly, I know)
select * from crm_1 where log < datepart(yyyy,getdate())
and log < datepart(mm,getdate())
and log < datepart(dd,getdate())
The aforementioned query doesn't find this value:
2005-06-09 08:27:17.810
CREATE TABLE [dbo].[CRM_1] (
[ipcliente] [varchar] (15) COLLATE Traditional_Spanish_CI_AS NOT NULL ,
[log] [datetime] NOT NULL)
GO
Thanks a lot and regards,I've elaborated on that topic here: http://www.karaszi.com/SQLServer/in...ime
.asp
Tibor Karaszi, SQL Server MVP
http://www.karaszi.com/sqlserver/default.asp
http://www.solidqualitylearning.com/
Blog: http://solidqualitylearning.com/blogs/tibor/
"Enric" <Enric@.discussions.microsoft.com> wrote in message
news:59611C1B-3D45-407E-B593-3D4CB5C9A0E8@.microsoft.com...
> Dear all,
> I've got some problems with date and time (very silly, I know)
> select * from crm_1 where log < datepart(yyyy,getdate())
> and log < datepart(mm,getdate())
> and log < datepart(dd,getdate())
> The aforementioned query doesn't find this value:
> 2005-06-09 08:27:17.810
> CREATE TABLE [dbo].[CRM_1] (
> [ipcliente] [varchar] (15) COLLATE Traditional_Spanish_CI_AS NOT NULL ,
> [log] [datetime] NOT NULL)
> GO
> Thanks a lot and regards,|||Try this:
select * from crm_1 where datepart(yyyy,log) < datepart(yyyy,getdate())
and datepart(mm,log) < datepart(mm,getdate())
and datepart(dd,log) < datepart(dd,getdate())
Or better yet, do some more reading as Tibor suggests.
ML|||It has been very useful. thanks a milion
"Tibor Karaszi" wrote:

> I've elaborated on that topic here: http://www.karaszi.com/SQLServer/in...i
me.asp
> --
> Tibor Karaszi, SQL Server MVP
> http://www.karaszi.com/sqlserver/default.asp
> http://www.solidqualitylearning.com/
> Blog: http://solidqualitylearning.com/blogs/tibor/
>
> "Enric" <Enric@.discussions.microsoft.com> wrote in message
> news:59611C1B-3D45-407E-B593-3D4CB5C9A0E8@.microsoft.com...
>